Online Test Instructions-
We had an online test on 2nd Jan. The instructions will be given by the TCS officials. Listen very carefully to the instructions. A silly mistake will prove very costly.
1. Open the internet explorer and type the address, given by TCS official, in the address bar.
2. The site opens and asks you login id and password. Those will also be provided to you.
3. Once you login, you might get a page âSample Testâ. Ignore it and click âGo to main Testâ on that same page. Now your test starts.
4. The test has 3 sections of 20 mins, 30 mins and 40 mins. Test starts with section 1.
5. On the right top corner you will have a timer counting down and links to ques of that section. From the timer you can see the time left for that section and through the ques links you can move to any ques within that section only.
6. The ques links have 3 color codes- Red â Not Visited
Orange- Visited But not attempted
Green- Attempted
7. There will be two buttons at the bottom of the page- Exit and Submit
8. After answering a ques click the Submit button to register your answer. You can always come back and change it within the stipulated time.
9. EXIT button takes you out of the section. So click it ONLY after you have attempted all ques of a section.
10. After you finish all 3 sections CLICK EXIT. DONâT close the main window WITHOUT clicking EXIT!
Online Test-
The test is divided into 3 sections. There is NO negative marking and NO sectional cut off.
VERBAL SECTION: ( antonyms ,synonyms n reading comprehension) :
10 antonyms were there and
10 synonyms were there , all from BARRON'S GRE 12TH EDITION exercise n model test paper with same options.
2 reading comprehension was there . Mainly they are para completion.
APTITUDE SECTION :
1)My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed?
6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00
Sol) The destination place is 80 degree west to the starting place. Hence the time difference between these two places is 5 hour 20 min. (=24hr*80/360). When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours). Hence, the time at the destination place is 12 noon - 5:20 hours = 6: 40 AM
2) In a two-dimensional array, X (9, 7),with each element occupying 4 bytes of memory, with the address of the first element X (1, 1) is 3000, find the address of X (8, 5)
Sol) initial x (1,1) = 3000 u have to find from x(8,1)so u have x(1,1),x(1,2) ... x(7,7) = so u have totally 7 * 7 = 49 elements you need to find for x(8,5) ? here we have 5 elements each element have 4 bytes : (49 + 5 -1) * 4 = 212 -----( -1 is to deduct the 1 element ) 3000 + 212 = 3212
3) what's the answer for that : A, B and C are 8 bit no's. They are as follows:
A -> 1 1 0 0 0 1 0 1
B -> 0 0 1 1 0 0 1 1
C -> 0 0 1 1 1 0 1 0 ( - =minus, u=union)
Find ((A - C) u B) =?
Sol)To find A-C, We will find 2's compliment of C and them add it with A, That will give us (A-C) 2's compliment of C=1's compliment of C+1 =11000101+1=11000110 A-C=11000101+11000110 =10001001
Now (A-C) U B is .OR. logic operation on (A-C) and B 10001001 .OR . 00110011 The answer is = 10111011,
Whose decimal equivalent is 187.
a. LINUX b. WINDOWS 98 c. SOLARIS d. SMTP
b. JAVA b. LISP c. Small talk d. Eiffel
c. HTTP b. ARP c. SMTP d. SAP
d. Linux b.windows NT c. SQL server d. UNIX
e. SAP b. ARP c. WAP d.TCP IP
f. Oracle b. Linux c. Ingress d. DB2
g. SMTP b. WAP c. SAP d. ARP
h. WAP b. HTTP c. BAAN d. ARP
i. SQL b. DB2 c. SYBASE d. HTTP
9)The size of a program is N. And the memory occupied by the program is given by M = square root of 100N. If the size of the program is increased by 1% then how much memory now occupied ?
Sol) M=sqrt(100N) N is increased by 1% therefore new value of N=N + (N/100) =101N/100
M=sqrt(100 * (101N/100) )
Hence, we get M=sqrt(101 * N)
10)A power unit is there by the bank of the river of 750 meters width. A cable is made from power unit to power plant opposite to that of the river and 1500mts away from the power unit.The cost of the cable below water is Rs.15/- per meter and cost of cable on the bank is Rs.12/-per meter. Find the total of laying the cable.
sol)750*15+(1500-750)*12=20250
11) Which shape will be obtained by using these values of X & Y?
X Y
0 0.00001
10 1.02
100 1.72
1000 3.00
9999 4.72
Sol): Y= log10(X)
Sol): I
18)If VXUPLVH is written as SURMISE, what is SHDVD is written as?Sol): PEASA
19)A power unit is there by the bank of the river of 900 mtr width. a cable is made from power unit to power a plant opposite to that of the river and 3000 mtr away from the power unit. The cost of the cable bellows water Rs5 / mtr and cost of cable on the bank is Rs 4/ mtr. Find the pt where the cable cut through the river.Sol): Method is (70/100*60/100*90/100)*100 = 37.8
So, economy = 100-37.8 = 62.2
21)g[0]=1,g[1]=-1,g[n]=2*g[n-1]-3*g[n-2] then calculate g[4]= ?sol)Let highest temp be x
so low temp=1/3 of x of 1/2 of x plus x/2 i.e. x/6+x/2
total temp=x+x/6+x/2=100
therefore, x=60
Lowest temp is 40
23)If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319 ? 1. Mammal - cow ---> a. A type of
2. Snake - reptile ---> b. A part of
3. Roof - Building ---> c. Not a type of
4. Mushroom - Vegetables ---> d. A superset of
sol) There is a simple way to answer this kind of Q's given 2x+3y=100, take l. of 'x' coeff and 'y' coeff i.e. l. of 2,3.2*3=6then divide 100 with 6 , which turns out 16 hence answer is 16
28)Amal bought 5 pens, 7 pencils and 4 erasers. Rajan bought 6 pens, 8 erasers and 14 pencils for an amount which was half more than what Amal had paid. What % of the total amount paid by Amal was paid for pens?
sol) Let, 5 pens + 7 pencils + 4 erasers = x rupeesso 10 pens + 14 pencils + 8 erasers = 2*x rupees
also mentioned, 6 pens + 14 pencils + 8 erarsers = 1.5*x rupees
so (10-6) = 4 pens = (2-1.5)x rupees
so 4 pens = 0.5x rupees => 8 pens = x rupees
so 5 pens = 5x/8 rupees = 5/8 of total (note x rupees is total amt paid by
amal) i.e 5/8 = 500/8% = 62.5%sol)Two people work together in 24 mins.
So, their one day work is
(1/x)+(1+y)=(1/24)
One man can complete the work in 40mins
one man's one day work (1/y)= (1/40)
Now,
(1/x)=(1/24)-(1/40)
(1/x)=(1/60)
So, x can complete the work in 60 minssol)10min:::assume he started at 1:00,so at 1:30 he met cart .He returned home at 2:00.so it took him 1 hour for the total jorney.by doing this he saved 20 min.so the actual time if the plane is not late is 1 hour and 20 min.so the actual time of plane is at 1:40.The cart travelled a time of 10 min before it met him.so the plane is 10 min early.
31,32.Two questions were on graphs . Practice graphs of tanx , logx , e^x.->What % people speak all the three languages?
->What % people speak German but not English?
CRITICAL REASONING SECTION:
This is also another scoring section. it consist of three passages with four questions each .Mainly the questions come from 12th edition of Barrons GRE.I prepared for CAT so it is one the easiest section for me. Dont mug from Barrons ...a little bit sense of logical reasoning is enough to score good in this section.
TECHNICAL INTERVIEW AND HR ROUND :
before going 2 an interview
1.prepare 4 tell me abt ur self ,family background ,strength, weakness type qstn
2.remember all d subs semester wise
3.know about ur project work. they will ask ques on your project work and from fav subjects
4.brush up ur basics in every subject, remember some imp defs n formulae
5.u must knw c language well
6.know abt d company (listen d preplacement talk keenly n write imp points )
7.give ur answers confidently n wid a smooth voice
and you will b through