Quantitative Aptitude-More exercise questions updated on Oct 2020
The concept of percentage is required in many other quantitative aptitude topics Profit/Loss, Ratio/Proportion, Number theory and Data Interpretation also. Also, there is a separate section of percentages in the quantitative aptitude which holds good weightage and thus, percentage is considered as one of the most important topics. A percentage is a number or ratio expressed as a fraction of 100. So 20%, means 20/100. Percentage is one of the simplest tools for the comparison of data as it helps to compare between different fractions when the denominator or the total number is different in each case. Candidates should know the Best ways to work out percentages problems so that they can solve the problems quickly in the competitive exams.

# Percentages-Exercise Questions

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1. What percent is 2 minutes 24 seconds of an hour?

a. 6%

b. 2%

c. 4%

d. 8%

2 . Adding  20%  of  x  to  x  is  equivalent  to  multiplying  x  by  which  of  the  following?

a. 12.5

b. 1.05

c. 1.15

d. 1.20

3 . What is the value of  81/3%  of   600+  37 ½  of  400

a. 100

b. 300

c. 150

d. 200

4.  Two  third  of  three fifth   of  five  sixth  of  a  number  is  what  percentage  of  that  number?

a. 66 2/3 %

b. 33 1/3 %

c. 60%

d. 40%

5.  Due  to fall  in manpower , the production  in a factory  decreases  by  40%, By  what  percentage   should  the  working  hours  be  increased  to  restore  the  original  level  of  production?

a. 66 2/3 %

b. 46 1/3 %

c. 25%

d. 40%

6. The salary  of  all officers  is  increased  twice successively  by  20%.  What  is  the  net  percentage  increase  in  their  salaries?

a. 20%

b. 40%

c. 21%

d. 44%

7. In  an  examination  it  is  necessary  for  a  candidate  to  get   45 %  of  the  maximum  marks  to  pass. A  candidate  who  gets  180  marks, fails by  45 marks. Find  the  maximum  marks.

a. 450

b. 600

c. 500

d. 550

8. 10 litres  of  water  is  added  to  50 litres  of  a  solution  containing  20%  of  alcohol  in  water . What  is  the  strength  of  alcohol  in  the  solution  now ?

a. 20%

b. 16 2/3 %

c. 12 1/2 %

d. 33 1/3 %

9. The  population  of a town  increase  annually by 20% .  If  the  present   population  is  2,00,000, then  what  is  the  difference  in  population  after  two  years  and  three years

a. 63,250

b. 48,800

c. 60,800

d. 57,600

10. Population  of  a  city  decreases  by  10%  at  the  end  of  first  year  and  increases  by   10%  at  the  end  of  second  year  and  again  decreases  by  10%  at  the  end  of  third  year.  If  the  population  of  the  city  at  the  end  of  third  year  is  4455,  then  what  was  the  population  of  the  city  at  the  beginning  of  the  first  year?

a. 5,000

b. 4,500

c. 4,950

d. 1,000

11. If  the  price  of  an  article  decreases  by  111/9 % and  the  sale  of  the  article  increases  by  12 ½ %,  what  is  the  net  effect  on  revenue?

a. 1% loss

b. 1% gain

c. No loss or no gain

d. Cannot  be  determined

12. In  an  exam  80%  of  the  boys  and  40%  of  the girls  passed.  The number  of  girls  who  passed  is  120, which  is  2/3rd of  the  number  of  boys  who  failed.  What  is  the  total  number  of  students  who  appeared  for  the  exam?

a. 1200

b. 380

c. 3800

d. 2180

13. The  population of  cities  A and B is equal. The  population  of  city A  increases  in  two  successive  years  by  20%  and  15%  respectively and  that  of  city  B  increases  successively  by  20%  and  10%  respectively.  If  the  difference  in  the  population  of  two  cities  after  2  years  is  768,  then  what  was  the  total  population  of  the  two  cities  initially?

a. 12,800

b. 26,500

c. 24,600

d. 25,600

14.  What  quantity   of  water  should  be added  to  reduce  5 litres  of  45%   acidic  liquid   to  25%   acidic  liquid?

a. 3litres

b. 2litres

c. 4litres

d. 4.5litres

15.  A, B, and  C  contest  an  election  from  a particular  constituency.  A  and  B  together  got  50%  more  votes  than  C.  The  vote  share  of   A  and  C  together  is  30  percentage  points  more  than  the  vote  share  of  B. Who  won  the  election?

a. A

b. B

c. C

d. Cannot  be  determined

16. In  an  examination  amar  got  8%  less  than  the  pass  mark  and  mohan  got  20%  more  than  the  pass  mark.  If  the  difference  between  the  percentage  of  their  mark  is  14,  then  what  is  the  pass  percentage

a. 40%

b. 50%

c. 60%

d. cannot  be  determined.

17. The  salaries  of  A and  B  together  is  Rs. 14,000. A spend 80%  of  his  salary  and  B  spends  85%  of  his  salary. What  is  the  salary  of  B  if  their  savings  are  equal?

a. Rs. 6,000

b. Rs. 8,000

c. Rs. 7,500

d. Rs. 6,500

18. A  sum  of  Rs. 395  was   divided  among  A, B, and  C  in  such  a  way  that  B  gets  25%  more  than  A  and  20%  more  than  C.  What  is  the  share  of   A?

a. Rs.195

b. Rs.180

c. Rs. 98

d. Rs. 120

19. There  are  three  positive  intigers  such  that  70%  of the  first  number ,  58 1/3% of  second  number  and  38 8/9%  of  the  third  number  are  all  equal.  Which  of  the  following  can  those  three  numbers  be?

a. 5,6,9

b.10,12,18

c.15,18,27

d. All  the  three

20.  Three  times  a number  is 20%  more  than  twice  another  number   when  increased  by  105.  If  twice the first  number increased  by 36  is 20%  less  than  three  times  of  the  second  number,  then  what  is  the  first  number?

a. 150

b.162

c. 180

d.None of  these

1. 2mt 24s =144s

144*100/60*60=4%

2. 120x/100= 1.2*x

3. 25*600/300 +  75*400/200  =50+150= 200

4. 2/3*3/5*5/6 =1/3

1/3 x/ x*100 = 100/3 =  33 1/3 %

5. Increase in working hours   40*100/100-40 =4000/60 =66 2/3 %

6. M . F   =  120/100*120/100 =  36/25

Net  %  increase    =  (  M . F  -1 ) *100  =(  36/25-1) * 100

11/25 *100 =  44 %

7. Let  max .  mark  =  x

pass  mark  =45x/100

180 = 45x/100-45

x =  180*100-4500/45 =500

8. Quantity  of  alcohol  in  50 litres  =  50*20/100  =10

strength  in  60 litre  solution  =  10/60*100  =  100/6  = 16 2/3

9. M .F  for  2Yrs  =  120/100*120/100 =36/25

M .F  for   3Yrs  =120/100*120/100*120/100 =6/5*6/5*6/5 =216/125

Population  after  2Yrs   =  2,00,000*36/25 =  2,88,000

Population  after  3 Yrs   =  2,00,000*216/125 = 3,45,600

Difference    =   3,45,600 – 2,88,000  =57,600

10. M. F  =  90/100*110*100*90/100 =  81*11/1000

Population  before  3Yrs  =  I.Q /M. F =  4455*1000/81*11 = 5000

11. M. F 1 = 100-100/9/100 =800/900 = 8/9

M. F  2 = 100+25/2/100 =225/200 =9/8

Total  M. F  =8/9*9/8 = 1

Overall  %  change  =  ( M. F – 1 ) *  100  = ( 1 – 1 ) * 100 =  0

12. Let  the Number of  boys  = x ,   Number  of  girls  =y

40y/100 =120

y  =  300

120=  2/3* 20x/100 = 2x/15

x  =  900

Total  =  x+y  =  300+900 =1200

13. Population  of  city  A =  Population  of  city  B  =  A

M . F  of   A  =   120/100*115/100 =  138/100

M . F  of   B   =   120/100*110/100 =132/100

Population  of  A  after  2  years    =    A*138/100

Population  of  B  after  2  years    =     A*132/100

Difference   =    A/100( 138 –132 )   =  768

A   =   768*100/6  =   12800

Total  initial  population   =  12800+12800  =  25,600

14. Quantity  of  acid  in  5litres  =45*5/100  =  2.25litres

Let  X  litres  of  water  is  added  to  the  solution,  then  there  is  2.25litres  of  acid  in  ( 5+  X )
Litres  of  liquid.

25%  of  ( 5 + X )  =   2.25,     25/100*  ( 5 + X )   =  2.25

X   =   225-125/25  =   4

15. Let a,b,c be the  vote  share  of  A, B, C  respectively

a + b  =  1.5 c

a + c   =  b + 30

a + b + c   = 100,    2b + 30 =  100,

b  =  35

a  =   25,  c =  40,  So, C  won  the  election.

16. Let  P  be  the  pass  percentage,  then

Amar  got  0.92 P% and  mohan  got  1.2 p%

Given  that,  1.2 P – 0.92 p  =  14

P  =14/0.28  =  50%

17. Let  the  salaries  of  A  and  B are  X  and  Y  respectively

X  +  Y   =   14,000

Savings  of   A   =  20X/100  =  Savings   of   B   =  15Y/100

X  =  ¾  Y

3/4Y + Y   =   14,000,     7Y/4   =14,000,   Y   =8,000

18. Let  each  one’s  share  is  A,B and C respectively,  then

B  =125A/100  =  120C/100

A =100B/125 =4/5B,  C =  100B/120 =  5/6B

4/5B +B  +5/6B  =395,   79B/30  =395,  B =395*30/79 =150

A  =  4*150/5  = 120

19. All  the  three  are  in the  same  ratio

20. Let  the  two  numbers  be  x  and  y.

3x  =  1.2( 2y +105)

3x   =  2.4y  +126     ………………..(1)

2x +36  =  0.8(3y)

2x +36  =2.4y            ………………..(2)

x   =    162

The concept of percentage is required in many other quantitative aptitude topics Profit/Loss, Ratio/Proportion, Number theory and Data Interpretation also. Also, there is a separate section of percentages in the quantitative aptitude which holds good weightage and thus, percentage is considered as one of the most important topics. A percentage is a number or ratio expressed as a fraction of 100. So 20%, means 20/100. Percentage is one of the simplest tools for the comparison of data as it helps to compare between different fractions when the denominator or the total number is different in each case. Candidates should know the Best ways to work out percentages problems so that they can solve the problems quickly in the competitive exams. Freshersworld provides candidates with the questions and answers with explanations, aptitude test, Formulas, tips, tricks and shortcuts methods to solve the problems related to Percentages. How to Find Percentage of Marks Obtained? Divide the total scores with the marks obtained and then multiply the result with 100. What is 8 as percentage of 20? 40%