Persistence paper SGSITS
If there r n proceses and each process waits p time in waiting state then cpu utilization is-:
a) n(1-p)
b) n*p
A string of pages were given and no of page faults have to be found in LRU algorithm
here is a file server which provides locking for mutual exclusion . if any procees locks the file and abruptly terminated this will result in indefinitely locking .The solution they found is to implement a timer for locking of file i.e. if time outs then server assumes that file is indefinitely locked and terminate the process
a) this solution is perfect for mutual exclusion
b) this will solve indefinite locking
c) this will result in interleaving of file between processes
A critical section is
ans a set of instruction which is shared by many processes
There was a question on automata ans the resultant string will have even no of c
CFG was given
S -> 1 S 1
S-> 0 S 0
S -> 1 1
S -> 0 0
Find out the string
One singly circular ordered list is there if M elements are ti be inserted what will be the complexity of time
a) O(M*N)
b) O(M*(M+N))
c) O ((M+N) * log(M+N))
find postfix and prefix of
A + B * ( C + D ) / E + F
Find out shortest path from A to B
A B C D E
A 0 m
B m 0 2 2 m
C 0 5
D 0 6
E 0
From the following when 43 will not be found by binary search (a series was given with last element 43 in each)
From 100 999 find the prob. Of getting 3 digit no with no 7 in any of its digit
a) 18/25
b) 10/25
c) 729/1000
from the set {a,b,c,d,e,f}find no of arrangements for 3 alphabet with no data repeated
To save space which option is better
a) write all join operation than select than project
b) ---------,,------------------than project----select
c) ----------,,-----------------in b/w select and project
Employee = { e_no , salary, fname, lname}
Works_On = {e_no, p_no, hrs}
Project = {p_no, p_name}
select e_no from Employee where salary = salary
a) query invalid
Select fname ,lname from Employee where e_no in (select e_no from works_on where p_no =(select * from project))
a) name of Employee who works on all project
B tree is different from other
a) has fixed index file size
b) is better for queries like < <= > >=
c) searching will be easy
func(char *s1,char * s2)
{
char *t;
t=s1;
s1=s2;
s2=t;
}
void main()
{
char *s1=jack, *s2=jill;
func(s1,s2);
printf(%s %s ,s1,s2);
}
OUTPUT jack jill
void main()
{
int a[5] ={1,2,3,4,5},i,j=2;
for (i =0;i<5;i++ )
func(j,a[i]);
for (i =0;i<5;i++ )
printf(%d,a[i]);
}
func(int j,int *a)
{
j=j+1;
a=a+j;
}
oid main()
{
for (a=1;a<=100;a++)
for(b=a;b<=100;b++)
foo();
}
foo()
{ }
how many times foo will be called.
a) 5050
b) 1010
A hash table has a sie of 11 and data filled in its position like{3,5,7,9,6}how many comparisons have to be made if data is not found in the list in worst case
a) 2
b) 6
c) 11
packet switching is better than circuit switching coz
a) it takes less time
b) it takes less bandwidth
Addition of two sparse matrix in 3 tuple notation ---time 30 min
24a tree has 1000000 nodes than how many search r required to search a node
a) 25
A prgrm to arrange a string in order of occurrence of the character