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NEEPCO aptitude questions with answers Practice
1. January 1, 2005 was Saturday. What day of the week lies on Jan. 1, 2006?
A.Wednesday
B.Tuesday
C.Saturday
D.Sunday
Answer: Option D
Explanation:The year 2005 is an ordinary year. So, it has 1 odd day.
1st day of the year 2005 was Saturday.
1st day of the year 2006 will be 1 day beyond Saturday.
Hence, it will be Sunday.
2. It was Monday on Jan 1, 2007. What was the day of the week Jan 1, 2011?
A.Monday
B.Friday
C.Saturday
D.Wednesday
Answer: Option C
Explanation:On 31st December, 2006 it was Sunday.
Number of odd days from the year 2007 to the year 2010 = (1 + 2 + 1 + 1) = 5 days.
On 31st December 2010, it was Friday.
Thus, on 1st Jan, 2011 it is Saturday.
3. If in a village the population decreases by 20%, increases by 10% and increases by 10%, the new population is what percentage of the original population?
A. 96.8
B. 98.8
C. 100
D. none
Ans:A
4. A square garden has fourteen posts along each side at equal interval. Find how many posts are there in all four sides:
A.56
B.52
C.44
D. 60
Ans:B
Ex:(B) Reqd no. of posts = 4 (at the corners) + 4 × 12 (in between on the sides)
= 4 + 48 = 52
5. Average age of students of an adult school is 40 years. 120 new students whose average age is 32 years joined the school. As a result the average age is decreased by 4 years. Find the number of students of the school after joining of the new students:
A.1200
B.120
C. 360
D. 240
Ans:D
Ex:Let the original no. of students be x A.T.S. 40x + 120 × 32 = (x + 120)36 ⇒ x = 120
∴ Reqd no. of students after joining the new students
= x + 120 = 240
6. The sum of two numbers is 45 and their product is 500. The G.C.M. of the numbers is:
A.5
B. 9
C.10
D.15
Ans:A
Ex: Let the nos. be x, 45 – x A.T.S x(45 – x) = 500
x2 – 45x + 500 = 0 ⇒ x2 – 20x – 25x + 500 = 0
x(x– 20) – 25 (x – 20) = 0 ⇒ (x – 20) (x – 25) = 0
x = 25, 20. If one no. = 25 other no. = 45 – 25 = 20
G.C.M. of 25, 20 = 5
7. An alloy of zinc and copper contains the metals in the ratio 5 : 3. The quantity of zinc to be added to 16 kg of the alloy so that the ratio of the metal may be 3 : 1 is:
A.2 kg
B. 4 kg
C.3 kg
D.8 kg
Ans:D
8. A man on riding crosses a bridge in 5 minutes when riding is being done at 15 kmph. The length of the bridge is :
A. 125 m
B. 250 m
C. 1250 m
D. 2500 m
Ans: C
9. Ravi runs at 15.6 kmph. How many metres does he run in 2 minutes ?
A. 260. m
B. 312 m
C. 520 m
D. 1040 m
Ans:C
10. A person borrowed Rs. 500 at the rate of 5% per annum S.I. What amount will he pay to clear the debt after 4 years ?
A. Rs. 200
B. Rs. 550
C. Rs. 600
D. Rs. 700
Ans:C
11. Vikas can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 kmph and the rest at 5kmph.the total distance is?
A.5 km
B.6 km
C.4 km
D.8 km
Ans:B
EX: Let total distance be S total time=1hr24minA to T :: speed=4kmphdiistance=2/3ST to S :: speed=5kmdistance=1-2/3S=1/3S21/15 hr=2/3 S/4 + 1/3s /584=14/3S*3S=84*3/14*3= 6km
12. The average ages of three persons is 27 years. Their ages are in the proportion of 1:3:5.What is theage in years of the youngest one among them.
A.10
B.12
C.11
D.9
Ans:D
Ex: Let the age of three persons be x, 3x and 5x -- > 9x/3 = 27 -- > x = 9
13. It being given that √ 15 = 3.88, the best approximation to √5/3 is
A.0.43
B.1.89
C.1.29
D.1.63
Ans:C
EX: x = √5/3 = √5*3/3*3 = √15 /√ 9 = √15/3 = 3.88/3 = 1.29
14. Of the two-digit numbers (those from 11 to 95, both inclusive) how many have a Second digit greater than the first digit?
A.37
B.38
C.36
D.35
Ans:C
Ex:12 to 19 -- > 8
23 to 29 -- > 7
34 to 39 -- > 6
45 to 49 -- > 5
56 to 59 -- > 4
67 to 69 -- > 3
78 to 79 -- > 2
89 -- > 1
15. In a boat 25 persons were sitting. Their average weight increased one kilogram when One mangoes and a new man comes in. The weight of the new man is 70kgs. Find the Weight of the man who isgoing.
A.50 kgs
B.75 kgs
C.45 kgs
D.30 kgs
Ans:C
Ex: Weight increased per person is 1 kg. Total increase in weight = 25 kgs Weight of new man is 70 kgs,(Which means his weight is 25 kgs heavier)
The weight of the old man was 70 – 25 = 45 kgs
16. There are 200 questions on a 3 hr examination. Among these questions are 50Mathematics problems. It is suggested that twice as much time be spent on eachmaths problem as for each other question. How many minutes should be spent onMathematics problems
A.36
B.72
C.60
D.100
Ans:B
17. The value of (0.625 * 0.0729 * 28.9)/(0.0017 * 0.025 * 8.1) is
A.3825
B.3.825
C.38.25
D.382.5
Ans:A
Ex: The sum of decimal places in numerator and denominator being the same, decimal point can be removed
(625*729*289) / (17*25*81) = 3825
18. The size of a wooden block is 5 * 10 * 20 cm3. How many whole such blocks you will take to construct a solid wooden cube of minimum size?
A.6
B.8
C.12
D.16
Ans:B
Ex: Size of each cube = 5 cm So number of blocks = (5 * 10 * 20)/(5*5*5) = 8
19. Find the odd man out - 1050, 510, 242, 106, 46, 16, 3
A.510
B.242
C.106
D.46
Ans:C
Ex:
2nd term = (Ist term - 30) / 2 = (1050-30)/2 = 510
3rd term = (2nd term - 26) / 2 = (510-26)/2 = 242
4th term = (3rd term - 22) / 2 = (242-22)/2 = 110
So 106 is the answer.
20. Six bells commence tolling together and toll at intervals 2,4,6,8,10 and 12 seconds respectively. In 30 minutes how many times they toll together.
A.4
B.10
C.15
D.16
Ans:D
Ex: L.C.M. of 2,4,6,8,10,12 = 120
So they toll together after every 120 seconds i.e. 2 minutes. So in 30 minutes they toll together 30/2 + 1 = 16 times
