Venn diagrams are an efficient way of representing and analyzing sets and performing set operations. As such, the usage of Venn diagrams is just the elaboration of a solving technique. Problems that are solved using Venn diagrams are essentially problems based on sets and set operations. Therefore, before we move on to understanding Venn diagrams, the candidates first need to understand the concept of a set. Venn Diagrams is an alternate way of depicting sets.

Data Interpretation

Venn Diagram-Exercise Questions

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I. Directions for questions 1 to 5: These questions are based on the following diagram.

                                                                                     

Circle A represents even numbers from 2 to 50.

Circle B represents odd numbers from 2 to 50.

Circle C, represents prime numbers from 2 to 50.

 

1. How many elements are there in set A only?

    a. 25          b. 24         c. 23          d. 22

 

2. How many elements are there in set B only?

    a. 14          b. 25         c. 10          d. 13

 

3. How many elements are there in B n C?

    a. 14          b. 11         c. 24           d. 13

 

4. How many elements are there in A U C?

    a. 0            b. 1           c. 2             d. 3

 

5. How many elements are there in C' (complement of C)?

    a. 35          b. 25         c. 34           d. 14

 

II. Directions for questions 6 to 10: Read the following data and then answer the questions that follow.

 

In a class, there are 60 students. For every 8 students learning Judo there are 4 students who learn Karate. For every 14 students learning Judo there are 7 students who learn both Judo and Karate and 7 students learning none.

 

6. How many students learn only Karate?

    a. 20       b. 30     c. 0      d. 40

 

7. How many students learn only Judo?

    a. 20       b. 40     c. 0      d. 14

 

8. How many students learn both Karate and Judo?

    a. 0         b. 10     c. 60     d. 20

 

9. If the students who learn both Judo and Karate stop learning Judo, then what percentage of the total number of students learn Judo?

    a. 50%      b. 33 1/3%        c. 40%        d. 55%

 

10. If 50% of those learning only Karate stop learning Karate and start learning Judo, then what is the ratio of the number of students learning Judo to those learning Karate?

    a. 3 : 1      b. 2 : 1        c. 4 : 1      d. Cannot be determined

 

Answer & Explanations

I.                                                                     

Number of even numbers from 2 to 50 are 25.

Number of odd numbers from 2 to 50 are 24.

Number of prime numbers from 2 to 50 are 15.

 

1. Number of elements in set A only = 24

    i.e, the even numbers which are not primes. Choice (2).

 

2. There are 10 elements in only set B, i.e, there are 10 odd numbers which are not primes.   

     Choice (3).

 

3. There are 14 elements in B n C i.e, there are 14 odd prime numbers. Choice (1).

   

4. There is only one element in A n C i.e, 2 is the only even prime number. Choice (2).

 

5. Number of elements in C' = the elements which do not belong to the set C. There are

   (24 + 10) = 34 such numbers i.e, numbers are non primes. Choice (3).

 

II. From the given data, we get the following diagram.

 

Taken = 60 students

J : K = 8 : 4 = 2 : 1

J : Both : None = 14 : 7 : 7 = 2 : 1 : 1 @ 2x, x, x (After removing the ratio)

=> x + x + x = 3x = 60

= x = 20

Hence

        1. x = 20 students learn only Judo.

        2. None learn only Karate.

        3. x = 20 students learn both.

 

6. None learn only Karate. Choice (3)

 

7. 20 students learn only Judo. Choice (1)

 

8. 20 students learn both. Choice (4)

 

9. 20 students learn both Judo and Karate. If they stop learning Judo then only 20 students would
    learn Judo. The total number of students is 60.

    Percentage of class learning only Judo = 20/60 x 100

    = 33 1/3%.   Choice (2)

 

10. Since none learn only Karate, so the given statement does not make any sense. The number of
     students learning Judo therefore remains the same.

     2x = 2 x 20 = 40 students learn Judo.

     Ratio : 40 : 20 = 2 : 1.        Choice (2)

Venn diagrams are an efficient way of representing and analyzing sets and performing set operations. As such, the usage of Venn diagrams is just the elaboration of a solving technique. Problems that are solved using Venn diagrams are essentially problems based on sets and set operations. Therefore, before we move on to understanding Venn diagrams, the candidates first need to understand the concept of a set. Venn Diagrams is an alternate way of depicting sets. Venn Diagrams consist of closed shapes, generally circles, which represent sets. The capital letter outside the circle denotes the name of the set while the letters inside the circle denote the elements of the set. Another type of question that often comes under this chapter is intersection of various geometric structures. Each geometric structures will be having some elements of their own and each structure will bear some characteristics or class. Intersection of two or more structures will give an amalgamation that will change the property of each previous element by something new. We have to identify that and need to answer accordingly from the given options. Freshersworld provides students or job seekers with concept, solved questions on Venn diagrams. Questions and answers for placements, bank po and competitive exams on Venn diagrams, are also provided which would help candidates in getting jobs easily.
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