Tata Consultancy Services Aptitude-General Contributed by V.Dinesh Babu updated on Nov 2019

TCS APTITUDE PAPER 

 

If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319

 

log 0.317=0.3332 and log 0.318=0.3364

then

log 0.319=log0.318+(log0.318-log0.317)

0.3396

…………………

A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there

 

x= 2 kg Packs

y= 1 kg packs

 

x + y = 150     .......... Eqn 1

2x + y = 264   .......... Eqn 2

 

solve the Simultaneous equation;

 

x = 114

 

using Eqn 1,

 

114 + y = 150

so, y = 36

 

ANS :  Number of 2 kg Packs = 114.

………………………..

My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed?

6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00 

The Answer is 6:40 AM

 

The destination place is 80 degree west to the starting place. Hence the time difference between these two places is 5 hour 20 min. (=24hr*80/360).

 

When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours).

Hence, the time at the destination place is 12 noon - 5:20 hours = 6: 40 AM

 

A plane moves from 9˚N40˚E to 9˚N40˚W. If the plane starts at 10 am and takes 8 hours to reach the destination, find the local arrival time.

Since it is moving from east to west longitide we need to add both

ie,40+40=80

multiply the ans by 4

 

=>80*4=320min

convert this min to hours ie, 5hrs 33min

It take

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