RedpineLatest (2011)Test Pattern and latest questions asked
Three Sections
Three sections mentioned comprises total of 25 questions (weightage -not uniform)
and they carry 100 marks, time given will be 90 minutes..........!
Section: 1(ELECTRONICS)
Section: 2(COMPUTING)
Section: 3(APTITUDE)
Time Limit: 90 Minutes
Section:1(ELECTRONICS)
Simple realization of logic gates given, we have 2 find d output?
The maximum value of signed number that can be fit into 2 byte register?
Section:2(COMPUTING)
C,C++
Program to obtain value of 'k' and to obtain 'k' in d given program code u should have d knowledge of modular division
Section:3(APTITUDE)
Topics to concentrate
Equations Average and age Train problems Probablity Direction senseSome questions asked
Section:1(ELECTRONICS)
1.Simple realization of logic gates given, we have 2 find d output?
Sol: Have to know the properties of AND,NAND, EX-OR functions
2.The maximum value of signed number that can be fit into 2 byte register?
Sol: We know that byte consists of 8 bits and the left most bit consist of sign hence only seven bits represent the magnitude similarly for 2 byte register d left most bit i.e.,16th bit represent sign hence the max value can be obtained by placing all 1's in remaining 15 bit positions.
Therefore d value is: (2^15)-1=32767
3. Ideal op-amp sum was given and we have 2 find d output voltage?
Sol: It was difficult to draw d diagram i will explain d procedure so that u can b able 2 interpret d diagram easily
At terminal1: (2-V1)/5=(V1-Vout)/10;
At terminal2: (0-V2)/10=(V2-Vout)/100; as given it is ideal op-amp V1=V2;
By solving d above three equations we can get Vout=-5.5V
4.Given a series of three sources connected in a ckt with load resistor(R) and power delivered by them individually is given by 18W,50W,98W.What is the total power delivered when all the three sources r active?
Sol: E1^2/R=18W;
E2^2/R=50W; Equations formed by interpreting the given data
E3^2/R=98W;
Hence total power delivered when all the 3 sources r active is E^2/R;
where E=E1+E2+E3;(as they r connected in series)
By multiplying 1st&2nd eqs we get (E1*E2)/R=sqrt(18*50)=30W;
By multiplying 2nd&3rd eqs we get (E3*E2)/R=sqrt(98*50)=70W;
By multiplying 1st&3rd eqs we get (E3*E1)/R=sqrt(18*98)=42W;
Therefore total power delivered is:P=(E1^2+E2^2+E3^2+2E1E2+2E2E3+2E1E3)/R
P=18+50+98+2*30+2*70+2*42=68+98+60+140+84=166+200+84
Hence total power delivered P=450W
5.A 26Kbyte memory, there is memory it contains 12 address lines and 4 bit data bus, the number of these type of memories required to design 26Kbyte memory?
Sol: 26K byte=26*1024=26624 bytes
Address lines=12;memory occupied=2^12=4096 bytes
4 bit data bus memory can be neglected as it is very small
Hence 26624 bytes=N*4096 bytes;
=>N=26624/4096=6.5
Hence 7(6.5)type of memories r required to design 26Kbyte memory
6.The no of 2-input XOR gates required to design 19-input XOR gate?
Sol: Lengthy procedure........!
7.This questions was given based on rising n falling edges of a flip flop?
Sol: Have a brief look on the theory of flip flops
8.Conversion of given multiplexers to AND gates
9.Convert d following:
a)73(in decimal) to binary
b)octal to binary
c)decimal to hexadecimal.........!
Sol: To convert decimal number 2 binary divide d given decimal number by 2
To convert decimal number 2 hexadecimal/octal divide d given number by 16/8
To convert binary number 2 decimal multiply d digits with powers of 2
Section:2(COMPUTING)
10.Simple C programs(3 questions were given)
11.Program to obtain value of 'k' and to obtain 'k' in d given program code u should have d knowledge of modular division
Eg: 16 mod 7=remainder obtained when 16 is divided by 7 i.e.,2
12.A(m,n)=n+1,if m=0;
=A(m-1,A(m,n)),if m>0,n=0;
=A(m-1,A(n,1)),if m>0,n>0; then find A(2,2)
Sol: Looks simpler but takes lot of time 2 answer its based on mainly RECURSIVE function used in C language
Section:3(APTITUDE)
13.Six monkeys take 4 minutes to eat 6 bananas
a)How many minutes r required for 2 monkeys to eat 2 bananas
b)How many monkeys r required to eat 15 bananas in 15 minutes
Sol:a)From given data we can interpret as follows:
1 monkey in 1 minute eats 6/(4*6)=1/4th of a banana--------eq1
Therefore 1 monkey takes 8 minutes to eat 2 bananas which means that 2 monkeys can eat 2 bananas in just 4 minutes
b)Let us assume that 'N' monkeys r required to eat 15 bananas in 15 minutes
Therefore 1 monkey in 1 minute can eat 15/(15*N)=1/Nth of a banana-------eq2
By equating 1 and 2 we get 1/N=1/4;
=> N=4;Hence no.of monkeys required are 4
14.A man walking along a railway bridge heard d whistle sound of a train when he already 5/13th distance of a bridge. Then he runs n can be escaped from making accident with d train. If he had ran back from there to starting point he could be escaped. If the velocity of man is 12kmph.What is velocity of man?
Sol: By given data it is clear that man has to cover total distance of d bridge and 5/13th
distance of d bridge as he walked back. Let d distance of d bridge='x'
Hence total distance man has to cover=x+(5/13)x=(18/13)x
But train requires only 'd' distance to cover and also time taken by both must b same
=> Velocity of train=x/t;
Velocity of man=(18/13)x/t=12kmph;
=>x/t=(12*13)/18=26/3kmph
15.In a party 12 members had a board meeting and hands were shaken between them before and after d party. Therefore total no.of handshakes possible?
Sol:1 st person can shook his hand with other 11 persons=>handshakes possible=11
2nd person can shook his hand with other 10 persons=>handshakes possible=10
11th person can shake hand with 1 person only=>handshakes possible=1
Hence total no.of handshakes possible=11+10+9+8+.......+1=66
But hands had done it twice their work in d party. Therefore total no.of handshakes possible=2*66=132
16.The average age of 10 members of a given committee= average age of 10 members 4 yrs.’ ago because older member is replaced by a younger member. What is d age difference?
Sol: Present average of ages=(a1+a2+......+x)/10-------eq1;
Average of ages before 4 yrs ago=(a1+a2....-9*4+y)/10-----eq2;
By equating eqs 1&2 we get
x=y-36;
y-x=36=>the age difference is 36 yrs........!
17.Abbreviations from CN like.....
Sol: CDMA-Code division multiple access
FTP- File transfer protocol
IEEE-Institute for electrical and electronics engineers
I have covered d total test paper and make practice of these type of questions for getting into RPS(Red Pine Signals) wishing u all d best for your future........!
NOTE: These are the solutions written by me in my test hope they will be helpful for u I will be happy if any one of my friend get benefitted by this.....!
Digital:
It includes both STLD ,VHDL and Microprocessors.
1)Design 3:1 multiplexer using one tri-state buffer, AND gates and NOT gates.
2)The no of 2-input XOR gates required to design 19-inprt XOR gate?
3)A 26Kbyte memory, there is memory it contains 12 address lines and 4 bit data bus, the number of these type of memories required to design 26Kbyte memory?
4)Write a VHDL or Verilog HDL code for
input:a,clock,reset
output :out is assigned to 1 when a is '1' for two clock cycles.
5)what is the output of following fig.100ps is the delay for XOR gate and 50ps for AND gate .all +ve and -ve edges start at boundaries of nanoseconds.(actually the output of fig is A(B(notC)+(not B)C) ,and the waveforms are given).
6)design forwhich the output is 10MHz clock,input to that circuit is 30MHz.Communications:
7) What is shoran’s theorem?
8)X is Gaussianly distributed signal
a)p(X<=infinte)=?
b)X is zreo mean and a unit variance random variable,them find the mean and variance of y
y=2X+5;
9)because of error 000 is coded instead of 0 ,111insted of 1.then what is the error correction and error detection capability of the system?
10)A deterministic signal whose pdf is given then we have to find the minimum sampling frequency needed ?
Computers:
11)One question on bit rate.....(i didn't remember exactly)
12)What is the application os MS world and MSperfect application is?
13)Write a c code for factorial using recursion.
14)Some statements are given like
putup::then lift the pen move accordingly without drawing aline,
FD N::move forward (N distance)
LD N:: move left at an angle of 90 degrees then move N
RD N::move right at an angle of 90 degrees then move N
putdown::draw alin following instructions
15)what is the output of following code
putdown
FD 10
putup
LD 1
FD 2
putdown
RD 8 so on like is....
13)what is the output
int a[10]={0,1,2,3,4,5,6,7,8};
int *p=a;
printf("%d\n",*p++);
14)two general knowledge questions..
15)what is expansion of GMSK?
16)find out the 5 digit number in that 4th digit is 4 more than the second digit ,3rd digit is 3 less the 2nd digit and first is 3 times the last digit?
1)what is output for the following program.
#include<stdio.h>
main()
{
int *p,*q,i;
p=(int *)100;
q=(int *)200;
i=q-p;
printf("%d",i);
}
a)100 b)25 c)0 d)compile error
Ans : b) 25
2)what is output for the following program.
#include<stdio.h>
#define swap(a,b) temp=a,a=b,b=temp;
main()
{
int a=5,b=6;
int temp;
if(a>b)
swap(a,b);
printf("a=%d,b= %d",a,b);
}
a)a=5 b=6 b)a=6 b=5 c)a=0 b=6 d)None Ans : a a=5 b=6
3)what is output for the following program.
#include<stdio.h>
main()
{
unsigned char i;
for( i=0;i<300;i++)
{
printf("*");
}
}
a)299 b)300 c)infinite d)none ans: c (infinite)
4)what is output for the following program.
#include<stdio.h>
main()
{
int n=2;
int sum=5;
switch(n)
{
case 2:sum=sum-2;
case 3:sum*=5;
break;
default :sum=0;
}
printf("%d",sum);
}
a)15 b)0 c)6 d)none
ans: a (15)
5)/* what is the program indicates */
#include<stdio.h>
main()
{
char *q;
int *ip;
q=(char *)malloc(100);
ip=(int *)q;
free(ip);
}
a)it frees all allocated memory.
b)it frees 400 bytes of memory.
c)
d)segmentation fault.
6)What is output for the following program.
#include<stdio.h>
main()
{
int a=10,b=5;
if(a=a&b)
b=a^b;
printf("a=%d,b=%d",a,b);
}
a)a=0,b=5 b)a=10 b=5 c)a=0,b=0 d)none
Ans: a a=0,b=5
7)What is output for the following program.
#include<stdio.h>
main()
{
int a[5],i,*ip;
for(i=0;i<5;i++)
a[i]=i;
ip=a;
printf("%d",*(ip+3*sizeof(int)));
}
a)0 b)5 c)1 d)none
Ans: d (none)
8)What is the size of the structure.
#include<stdio.h>
main()
{
struct
{
char a;
short b;
int c;
}temp;
}
a)7 b)8 c)12 d)120
ans:b
9) What is output for the following program.
#include<stdio.h>
main()
{
unsigned char c[]={0x1,0x2,0x3,0x4,0x11,0x22,0x33,0x44};
unsigned int *p=c;
unsigned short *s=c;
printf("%x %x %x",c[2],p[2],s[2]);
}
Ans: please execute this program.
10) What is the difference between these two declarations:
i) int *f()
ii) int (*f)()
11) Define pointer to function that take argument as character pointer and return void pointer.
Ans: void *(*f)(char *)
12) 5-2-3*5-2 evaluates 18 then
i) - left associative * has precedence over -
ii) - right associative * has precedence over -
iii) * left associative - has precedence over *
iv) * right associative - has precedence over *
a) i b)ii c) iii d)iv
Ans: iv
DataStructure questions:
1)Difference between re-entrance and recursion.
2)In which Data structure recursion can be used.Ans: Stack.
3)Merge sort problem can be solved using which method. Ans: Divide and conquer strategy.
4)8 queens problem can be solved by using which method Ans: Back tracking.
5,6) Two problems related to inorder and post order.
First answer was : + - * a b c d (In objective its answer was (d) )
Second answer was : inorder
Operating systems:
1)what are the necessary conditions for Deadlockrefer Galvin
Answer was : b&c
2)Two problems on memory management .
One answer was : 68.5 ns(average access time.)
3) what are the different types of IPC mechanisms.
Ans:
1)direct communication.(messages)
2)Indirect communication.(mail box)
3) Synchronous/Asynchronous communication.(Naming.)
4) Context switching.
Ans : A
5) Specify any 3 regarding the context of process?
Ans:
1)Process state.
2) Process Attribute.
3)Accounting Information.
4)See PCB (Process control Block) in Galvin Book.
5)Advantages and Disadvantages of cache buffer?
6)Increasing memory many page faults occur(I dont know Question exactly)?
Ans: FIFO
Computer Networks
1)What is the use of ICMP in TCP/IP stack?
2)What is the use of ARP in TCP/IP stack?
3)What is the header length of Ether Net MAC.
4)What is the mechanisms used for error detection in Data Link Layer?
Ans: CRC(cyclic redundancy check.)