**TCS Placement-Paper : 44337**

# TCS Question-Paper placement paper Question and answers

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**TCS New placement papers model questions for learn and practice 2014-2015.TCS previous years solved question and answers with detailed explanations**

1. Ray writes a two digit number. He sees that the number exceeds 4 times the sum of its digits by 3. If the number is increased by 18, the result is the same as the number formed by reversing the digits. Find the number.

a) 35

b) 42

c) 49

d) 57

Solution: Let the two digit number be xy.

4(x + y) +3 = 10x + y .......(1)

10x + y + 18 = 10 y + x ....(2)

Solving 1st equation we get 2x - y = 1 .....(3)

Solving 2nd equation we get y - x = 2 .....(4)

Solving 3 and 4, we get x = 3 and y = 5

2. a, b, c are non negitive integers such that 28a+30b+31c = 365. a + b + c = ?

a) Greater than 14

b) less than or equal to 11

c) 13

d) 12

In a calender,

Number of months having 28 days = 1

Number of months having 30 days = 4

Number of months having 31 days = 7

28 x 1 + 30 x 4 + 31 x 7 = 365

Here, a = 1, b = 4, c = 7.

a+b+c = 12

3. George can do a piece of work in 8 hours. Paul can do the same work in 10 hours, Hari can do the same work in 12 hours. George, paul and hari start the same work at 9 am, while george stops at 11 am, the remaining

two complete the work. What time will the work complete?

a) 11.30 am

b) 12 noon

c) 12.30 pm

d) 1 pm

Let the total work = 120 units.

As George completes this entire work in 8 hours, his capacity is 15 units /hour

Similarly, the capacity of paul is 12 units / hour

the capacity of Hari is 10 units / hour

All 3 started at 9 am and worked upto 11 am. So total work done upto 11 am = 2 x (15 + 12 + 10) = 74

Remaining work = 120 - 74 = 46

Now this work is to be done by paul and hari. 46 / (12 + 10) = 2 hours (approx)

So work gets completed at 1 pm

4. If x^y denotes x raised to the power y, Find last two digits of (1141^3843) + (1961^4181)

a) 02

b) 82

c) 42

d) 22

5 J can dig a well in 16 days. P can dig a well in 24 days. J, P, H dig in 8 days. H alone can dig the well in How many days?

a) 32

b) 48

c) 96

d) 24

Assume the total work = 48 units.

Capacity fo J = 48 / 16 = 3 units / day

Capacity of P = 48 / 24 = 2 units / day

Capacity of J, P, H = 48 / 8 = 6 units / day

From the above capacity of H = 6 - 2 - 3 = 1

So H takes 48 / 1 days = 48 days to dig the well

6. If a lemon and apple together costs Rs.12, tomato and a lemon cost Rs.4 and an apple costs Rs.8 more than a lemon. What is the cost of lemon?

L + A = 12 ...(1)

T + L = 4 .....(2)

L + 8 = A

Taking 1 and 3, we get A = 10 and L = 2

7. 3 mangoes and 4 apples costs Rs.85. 5 apples and 6 peaches costs 122. 6 mangoes and 2 peaches costs Rs.144. What is the combined price of 1 apple, 1 peach, and 1 mango.

a) 37

b) 39

c) 35

d) 36

3m + 4a = 85 ..(1)

5a + 6p = 122 ..(2)

6m + 2p = 144 ..(3)

(1) x 2 => 6m + 8a = 170

4 x (3) => 6m + 2p = 144

Solving we get 8a - 2p = 56 ..(4)

(2) => 5a + 6p = 122

3 x (4) = 24a - 6p = 168

Solving we get a = 10, p = 12, m = 15

So a + p + m = 37

8. An organisation has 3 committees, only 2 persons are members of all 3 committee but every pair of committee has 3 members in common. what is the least possible number of members on any one committee?

a) 4

b) 5

c) 6

d) 1

From the (iii) clue, peda must be eaten after jilebi. so Peda should not be eaten on monday.

9. If YWVSQ is 25 - 23 - 21 - 19 - 17, Then MKIGF

a) 13 - 11 - 8 - 7 - 6

b) 1 - 2-3-5-7

c) 9 - 8 - 7 - 6 - 5

d) 7 - 8 - 5 - 3

MKIGF = 13 - 11 - 9 - 7 - 6

Note: this is a dummy question. Dont answer these questions

10. Addition of 641 + 852 + 973 = 2456 is incorrect. What is the largest digit that can be changed to make the addition correct?

a) 5

b) 6

c) 4

d) 7

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